cayley/graph/and_iterator_optimize.go
kortschak 60d5c60817 Canonicalise iterator receiver names
This apparently meaningless churn improves godoc readability.
2014-06-28 21:36:50 +09:30

330 lines
10 KiB
Go

// Copyright 2014 The Cayley Authors. All rights reserved.
//
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.
package graph
// Perhaps the most tricky file in this entire module. Really a method on the
// AndIterator, but important enough to deserve its own file.
//
// Calling Optimize() on an And iterator, like any iterator, requires that we
// preserve the underlying meaning. However, the And has many choices, namely,
// which one of it's subiterators will be the branch that does the Next()ing,
// and which ordering of the remaining iterators is the most efficient. In
// short, this is where a lot of the query optimization happens, and there are
// many wins to be had here, as well as many bad bugs. The worst class of bug
// changes the meaning of the query. The second worst class makes things really
// slow.
//
// The good news is this: If Optimize() is never called (turned off, perhaps) we can
// be sure the results are as good as the query language called for.
//
// In short, tread lightly.
import (
"container/list"
)
// Optimizes the AndIterator, by picking the most efficient way to Next() and
// Check() its subiterators. For SQL fans, this is equivalent to JOIN.
func (it *AndIterator) Optimize() (Iterator, bool) {
// First, let's get the list of iterators, in order (first one is Next()ed,
// the rest are Check()ed)
oldItList := it.GetSubIterators()
// And call Optimize() on our subtree, replacing each one in the order we
// found them. it_list is the newly optimized versions of these, and changed
// is another list, of only the ones that have returned replacements and
// changed.
itList := optimizeSubIterators(oldItList)
// Close the replaced iterators (they ought to close themselves, but Close()
// is idempotent, so this just protects against any machinations).
closeIteratorList(oldItList, nil)
// If we can find only one subiterator which is equivalent to this whole and,
// we can replace the And...
out := it.optimizeReplacement(itList)
if out != nil {
// ...Move the tags to the replacement...
moveTagsTo(out, it)
// ...Close everyone except `out`, our replacement...
closeIteratorList(itList, out)
// ...And return it.
return out, true
}
// And now, without changing any of the iterators, we reorder them. it_list is
// now a permutation of itself, but the contents are unchanged.
itList = optimizeOrder(itList)
// Okay! At this point we have an optimized order.
// The easiest thing to do at this point is merely to create a new And iterator
// and replace ourselves with our (reordered, optimized) clone.
newAnd := NewAndIterator()
// Add the subiterators in order.
for e := itList.Front(); e != nil; e = e.Next() {
newAnd.AddSubIterator(e.Value.(Iterator))
}
// Move the tags hanging on us (like any good replacement).
newAnd.CopyTagsFrom(it)
newAnd.optimizeCheck()
// And close ourselves but not our subiterators -- some may still be alive in
// the new And (they were unchanged upon calling Optimize() on them, at the
// start).
it.cleanUp()
return newAnd, true
}
// Closes a list of iterators, except the one passed in `except`. Closes all
// of the iterators in the list if `except` is nil.
func closeIteratorList(l *list.List, except Iterator) {
for e := l.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
if it != except {
e.Value.(Iterator).Close()
}
}
}
// Find if there is a single subiterator which is a valid replacement for this
// AndIterator.
func (_ *AndIterator) optimizeReplacement(itList *list.List) Iterator {
// If we were created with no SubIterators, we're as good as Null.
if itList.Len() == 0 {
return &NullIterator{}
}
if itList.Len() == 1 {
// When there's only one iterator, there's only one choice.
return itList.Front().Value.(Iterator)
}
// If any of our subiterators, post-optimization, are also Null, then
// there's no point in continuing the branch, we will have no results
// and we are null as well.
if hasAnyNullIterators(itList) {
return &NullIterator{}
}
// If we have one useful iterator, use that.
it := hasOneUsefulIterator(itList)
if it != nil {
return it
}
return nil
}
// optimizeOrder(l) takes a list and returns a list, containing the same contents
// but with a new ordering, however it wishes.
func optimizeOrder(l *list.List) *list.List {
out := list.New()
var bestIt Iterator
bestCost := int64(1 << 62)
// bad contains iterators that can't be (efficiently) nexted, such as
// "optional" or "not". Separate them out and tack them on at the end.
bad := list.New()
// Find the iterator with the projected "best" total cost.
// Total cost is defined as The Next()ed iterator's cost to Next() out
// all of it's contents, and to Check() each of those against everyone
// else.
for e := l.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
if !it.Nextable() {
bad.PushBack(it)
continue
}
rootStats := e.Value.(Iterator).GetStats()
projectedCost := rootStats.NextCost
for f := l.Front(); f != nil; f = f.Next() {
if !f.Value.(Iterator).Nextable() {
continue
}
if f == e {
continue
}
stats := f.Value.(Iterator).GetStats()
projectedCost += stats.CheckCost
}
projectedCost = projectedCost * rootStats.Size
if projectedCost < bestCost {
bestIt = it
bestCost = projectedCost
}
}
// TODO(barakmich): Optimization of order need not stop here. Picking a smart
// Check() order based on probability of getting a false Check() first is
// useful (fail faster).
// Put the best iterator (the one we wish to Next()) at the front...
out.PushBack(bestIt)
// ...And push everyone else after...
for e := l.Front(); e != nil; e = e.Next() {
thisIt := e.Value.(Iterator)
if !thisIt.Nextable() {
continue
}
if thisIt != bestIt {
out.PushBack(thisIt)
}
}
// ...And finally, the difficult children on the end.
out.PushBackList(bad)
return out
}
// optimizeCheck(l) creates an alternate check list, containing the same contents
// but with a new ordering, however it wishes.
func (it *AndIterator) optimizeCheck() {
subIts := it.GetSubIterators()
out := list.New()
// Find the iterator with the lowest Check() cost, push it to the front, repeat.
for subIts.Len() != 0 {
var best *list.Element
bestCost := int64(1 << 62)
for e := subIts.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
rootStats := it.GetStats()
projectedCost := rootStats.CheckCost
if projectedCost < bestCost {
best = e
bestCost = projectedCost
}
}
out.PushBack(best.Value)
subIts.Remove(best)
}
it.checkList = out
}
// If we're replacing ourselves by a single iterator, we need to grab the
// result tags from the iterators that, while still valid and would hold
// the same values as this and, are not going to stay.
// getSubTags() returns a map of the tags for all the subiterators.
func (it *AndIterator) getSubTags() map[string]bool {
subs := it.GetSubIterators()
tags := make(map[string]bool)
for e := subs.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
for _, tag := range it.Tags() {
tags[tag] = true
}
}
for _, tag := range it.Tags() {
tags[tag] = true
}
return tags
}
// moveTagsTo() gets the tags for all of the src's subiterators and the
// src itself, and moves them to dst.
func moveTagsTo(dst Iterator, src *AndIterator) {
tagmap := src.getSubTags()
for _, tag := range dst.Tags() {
if tagmap[tag] {
delete(tagmap, tag)
}
}
for k, _ := range tagmap {
dst.AddTag(k)
}
}
// optimizeSubIterators(l) takes a list of iterators and calls Optimize() on all
// of them. It returns two lists -- the first contains the same list as l, where
// any replacements are made by Optimize() and the second contains the originals
// which were replaced.
func optimizeSubIterators(l *list.List) *list.List {
itList := list.New()
for e := l.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
newIt, change := it.Optimize()
if change {
itList.PushBack(newIt)
} else {
itList.PushBack(it.Clone())
}
}
return itList
}
// Check a list of iterators for any Null iterators.
func hasAnyNullIterators(l *list.List) bool {
for e := l.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
if it.Type() == "null" {
return true
}
}
return false
}
// There are two "not-useful" iterators -- namely "null" which returns
// nothing, and "all" which returns everything. Particularly, we want
// to see if we're intersecting with a bunch of "all" iterators, and,
// if we are, then we have only one useful iterator.
func hasOneUsefulIterator(l *list.List) Iterator {
usefulCount := 0
var usefulIt Iterator
for e := l.Front(); e != nil; e = e.Next() {
it := e.Value.(Iterator)
switch it.Type() {
case "null", "all":
continue
case "optional":
// Optional is weird -- it's not useful, but we can't optimize
// away from it. Therefore, we skip this optimization
// if we see one.
return nil
default:
usefulCount++
usefulIt = it
}
}
if usefulCount == 1 {
return usefulIt
}
return nil
}
// and.GetStats() lives here in and-iterator-optimize.go because it may
// in the future return different statistics based on how it is optimized.
// For now, however, it's pretty static.
func (it *AndIterator) GetStats() *IteratorStats {
primaryStats := it.primaryIt.GetStats()
CheckCost := primaryStats.CheckCost
NextCost := primaryStats.NextCost
Size := primaryStats.Size
for _, sub := range it.internalIterators {
stats := sub.GetStats()
NextCost += stats.CheckCost
CheckCost += stats.CheckCost
if Size > stats.Size {
Size = stats.Size
}
}
return &IteratorStats{
CheckCost: CheckCost,
NextCost: NextCost,
Size: Size,
}
}